Calculator

Power Factor Correction Calculator

Calculate the capacitor size in kvar needed to raise power factor, and the reduction in apparent power and line current.

Updated 2026-10-07

Protection and MVFree, no sign-upFormula and worked example
Capacitor size needed42.1 kvar
Apparent power before125.0 kVA
Apparent power after105.3 kVA
Line current reduction15.8 %

Most industrial loads are inductive: motors, transformers and lighting ballasts draw reactive power as well as real power. The extra current heats cables, takes capacity from transformers and, on many tariffs, costs money. A capacitor bank supplies the reactive power locally and lowers the current drawn from the supply. This calculator finds the size of the bank.

Formula

Qc = P × (tan φ1 − tan φ2)
φ = cos⁻¹(power factor)

P is the real power in kW, φ1 the angle at the present power factor and φ2 the angle at the target. Qc comes out in kvar. The real power does not change, so the apparent power after correction is simply P divided by the new power factor.

Worked example

A plant draws 100 kW at a power factor of 0.80 and the target is 0.95.

Correcting to unity would take 75 kvar, which is the full reactive power of the load. Going from 0.95 to unity costs a lot of extra capacitance for a small further gain, which is why targets of 0.95 to 0.98 are common.

How a bank is built

Banks are built from stock capacitor sizes, so the result is rounded up to the next available step, or split into steps of a controller-switched bank when the load varies. A fixed bank sized for the maximum demand overcorrects at light load. A power factor controller, switching steps in and out, tracks the load. For a single motor, the capacitor can be connected at the motor terminals, but the size must not exceed the limit the motor manufacturer gives, otherwise a self-excited overvoltage can occur when the motor is switched off while the capacitor stays connected.

Harmonics are the main trap

Capacitors and the supply inductance form a resonant circuit. If the resonant frequency sits near a harmonic produced by drives, rectifiers or other non-linear loads, the capacitors can draw high currents and fail, and voltage distortion rises. Where such loads are a large part of the demand, the bank is fitted with series detuning reactors, which move the resonance below the lowest significant harmonic, and the harmonic spectrum is measured before the bank is chosen. This calculation assumes a sinusoidal load.

What else to check

Common mistakes

Questions

What power factor should I target?

Utility tariffs and rules differ. A target of 0.95 is common, but check the tariff, which may set a penalty threshold.

Why does correction reduce the line current but not the energy used?

The kW stay the same. Only the reactive component, which does no work, is removed from the supply side.

Can I correct at the main incomer instead of at each motor?

Yes, and it is cheaper. It lowers the current in the supply and the transformer, but not in the cables between the incomer and each motor.

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